# 12 coins riddle

Decision Trees – Fake (Counterfeit) Coin Puzzle (12 Coin Puzzle). Difficulty Level: Hard; Last Updated: 31 Jul, Let us solve the classic “fake coin” puzzle. To experiment with this puzzle, you can try out the 12 coins puzzle game (made By means of a simple weighing, we can determine which one is the fake coin. The coins 7, 9, 11, and 12 are treated oppositely. If the counterfeit coin is 7 and is heavier than the other coins, then, in the first weighing, the right pan goes down,.

McWorter for the following discussion. It is not possible to do any better, since any coin that is put on the scales at some point and picked as the counterfeit coin can then always be assigned weight relative to the others. This is now the complete answer to 12 coins riddle 12 coin problem. If we proceed as in Problem 1, we will

### : 12 coins riddle

CANADA BITCOIN REDDIT | What bitcoin to buy now |

12 coins riddle | Koto coin price |

WHAT BITCOIN TO BUY NOW | 393 |

ALICE PAUL GOLD COIN | Using number theory to solve this problem gives us one more marble and an unexpected hilarious twist. Fabulously interesting. This means that one of the three coins that was removed from the heavier side is the heavy coin. In this case you just need 12 coins riddle weigh the remaining coin against 12 coins riddle of the other 11 coins and this tells you whether it is heavier, lighter, or the same. Another alternative solution by Frank Cole Probably in the early 60's, we enjoyed a pre-determined solution which enabled mental calculation of the result; pre-determined in the sense that the 3 set-ups are in writing before any weighings, thus eliminating adjustments at weighings II and III. When possible, we should group the coins 12 coins riddle such a way that every branch is going to yield valid output in simple terms generate full 3-ary tree. |

12 coins riddle | I 12 coins riddle he got a kick out of things like that. Weigh 4 against 9, a known good marble. Case 12 coins riddle : A marble participates in only one weighing. So 40 years after, I told my Dad that I solved the problem. Number the coins from 1 to 13 and the authentic coin number 0 and perform these weighings in any order: 0, 1, 4, 5, 6 against 7, 10, 11, 12, 13 0, 2, 4, 10, 11 against 5, 8, 9, 12, 13 0, 3, 8, 10, 12 against 6, 7, 9, 11, 13 If the scales are only off balance once, then it must be one of the coins 1, 2, 3—which only appear in one weighing. |

*12 coins riddle*generate best decision tree. Then any one of these marbles could be the different marble.